![]() It is already known that whatever the coefficients are, those proportions must hold: This removes the first four equations of the system. K 2SO 4 has to be 2a (because of K), and also, FeSO 4 has to be 1a (because of Fe), CO has to be 6a (because of C) and (NH 4) 2SO 4 has to be 3a (because of N). Start with the one among those which has a big index (this will help to keep working with integers), and assign a variable, such as a. Identify elements which occur in one compound in each member. To speed up the process, one can combine both methods to get a more practical algorithm:ġ. Which means that all coefficients depend on a parameter a, just choose a=1 (a number that will make all of them small whole numbers), which gives: Solve the system (Direct substitution is usually the best way.) So, for each element, count its atoms and let both sides be equal.ģ. There must be the same quantities of each atom on each side of the equation.
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